Add inplace option to DataFrame.update()

[dov]

Currently DataFrame.update() modifies the dataframe in place. I feel this is not symmetric to how most other methods work, e.g. set_index(), that returns a new DataFrame. It is probably too late to change this default behavior (isi it?), but if at the very least an inplace option was added (with default value True to support the current behaviour), it will be easier to chain a sequence of operators that includes update().

[jreback]

can you show an example of your use case. .update has a very limited usecase, often .combine/.combine_first/.assign can substitue.

As far as the default, this ship has sailed, would be better to introduce a .updated that defaults to returning a new object (and has an inplace parameter), and deprecate .update. Would take a PR for that.

[dov]

I first encountered update as an answer to my stackoverflow question:

http://stackoverflow.com/questions/31769754/looking-up-multiple-values-from-a-pandas-dataframe/31779537#31779537

regarding how to a "parallell lookup" from all rows of one DataFrame by the values of another DataFrame.

In that example it might be useful to directly after the call to update() e.g. write the resulting dataframe to a csv file.

[Safrone]

I had a similar feeling. Is there a way to do this in a more functional way?

[giuliobeseghi]

can you show an example of your use case. .update has a very limited usecase, often .combine/.combine_first/.assign can substitue.

As far as the default, this ship has sailed, would be better to introduce a .updated that defaults to returning a new object (and has an inplace parameter), and deprecate .update. Would take a PR for that.

My use case is:

# combine three datetime series referring to periods that partially overlap
overall_forecast = long_term_forecast.update(medium_term_forecast).update(short_term_forecast)

I can't use loc because the index of a series is not necessarily contained in another

[Liam3851]

@giuliobeseghi If I understand correctly, it sounds like your use case would be solved by using combine_first instead of update?

Combine Series values, choosing the calling Series's values
first. Result index will be the union of the two indexes

Parameters
----------
other : Series

[giuliobeseghi]

@giuliobeseghi If I understand correctly, it sounds like your use case would be solved by using combine_first instead of update?

Combine Series values, choosing the calling Series's values
first. Result index will be the union of the two indexes

Parameters
----------
other : Series

You are right.

Thanks for that, I got confused with the example: I might have to keep the nans of the most recent series. I realised I can do with reindex + loc:

import pandas as pd
import numpy as np

s = pd.Series([1, 2, 3, 4, 5])
t = pd.Series([10, 11, 12], index=range(3, 6))
t.iloc[1] = np.nan
print(t)

res = s.reindex(t.index | s.index)
res.loc[t.index] = t.to_numpy()
print(res)

It would be good if combine_first had an option to overwrite values even if thery're np.nan :)

[giuliobeseghi]

Shall we suggest combine_first in the docs of Series.update and DataFrame.update?

"For non-inplace update consider combine_first"