ENH: `applymap` get kwargs?

[attack68]

apply has kwargs whilst applymap does not. Is there a specific reason for this?

it's straight forward to do

apply(f, **kwarrgs)

or

g = partial(f **kwargs)
applymap(g)

its not documented how this can be achieved with partial which the more casual user might miss?

[alexprincel]

I may attempt a PR on this unless someone disagrees with the approach but it seems like the simplest solution would be to modify the func variable in pandas.frame.applymap to be the result of functools.partial(func, **kwargs). Obviously, this requires adding **kwargs as an argument, modyfing the docs and adding tests.

I tested locally the aforementioned change and obtained this output from the following interactive session:

>>> def test(x, b=2):
...    return x + b
... 
>>> df = pd.DataFrame({'a': [1, 2], 'b': [3, 4]})
>>> df.applymap(test, b=5)
   a  b
0  6  8
1  7  9
>>> df.applymap(test)
   a  b
0  3  5
1  4  6
>>> df.applymap(lambda x, y: x + y, y = 2)
   a  b
0  3  5
1  4  6