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satish said...

int a[]= {10,3,0,1,45,22,667,8,99,0,3};
int min = a[0];
int max = a[1];
int minPos = 0;
int maxPos = 1;
if(maxa[i]) {
min = a[i];
minPos = i;
}
if(max<a[i]) {
max = a[i];
maxPos = i;
}

}
System.out.println("min : "+ min +" Pos : "+(minPos+1));
System.out.println("max : "+ max +" Pos : "+(maxPos+1));

Apr 2, 2018, 1:20:30 PM

Posted to How to find largest and smallest number from integer array - Java Solution