Find last index of a character in a string Last Updated : 27 Jul, 2022 Comments Improve Suggest changes Like Article Like Report Try it on GfG Practice Given a string str and a character x, find last index of x in str. Examples : Input : str = "geeks", x = 'e' Output : 2 Last index of 'e' in "geeks" is: 2 Input : str = "Hello world!", x = 'o' Output : 7 Last index of 'o' is: 7 Recommended PracticeLast index of a character in the stringTry It! Method 1 (Simple : Traverse from left): Traverse given string from left to right and keep updating index whenever x matches with current character. Implementation: C++ // CPP program to find last index of // character x in given string. #include <iostream> using namespace std; // Returns last index of x if it is present. // Else returns -1. int findLastIndex(string& str, char x) { int index = -1; for (int i = 0; i < str.length(); i++) if (str[i] == x) index = i; return index; } // Driver code int main() { // String in which char is to be found string str = "geeksforgeeks"; // char whose index is to be found char x = 'e'; int index = findLastIndex(str, x); if (index == -1) cout << "Character not found"; else cout << "Last index is " << index; return 0; } Java // Java program to find last index // of character x in given string. import java.io.*; class GFG { // Returns last index of x if // it is present Else returns -1. static int findLastIndex(String str, Character x) { int index = -1; for (int i = 0; i < str.length(); i++) if (str.charAt(i) == x) index = i; return index; } // Driver code public static void main(String[] args) { // String in which char is to be found String str = "geeksforgeeks"; // char whose index is to be found Character x = 'e'; int index = findLastIndex(str, x); if (index == -1) System.out.println("Character not found"); else System.out.println("Last index is " + index); } } /* This code is contributed by Prerna Saini */ Python3 # A Python program to find last # index of character x in given # string. # Returns last index of x if it # is present. Else returns -1. def findLastIndex(str, x): index = -1 for i in range(0, len(str)): if str[i] == x: index = i return index # Driver program # String in which char is to be found str = "geeksforgeeks" # char whose index is to be found x = 'e' index = findLastIndex(str, x) if index == -1: print("Character not found") else: print('Last index is', index) # This code is contributed by shrikant13. C# // C# program to find last index // of character x in given string. using System; class GFG { // Returns last index of x if // it is present Else returns -1. static int findLastIndex(string str, char x) { int index = -1; for (int i = 0; i < str.Length; i++) if (str[i] == x) index = i; return index; } // Driver code public static void Main() { // String in which char is to be found string str = "geeksforgeeks"; // char whose index is to be found char x = 'e'; int index = findLastIndex(str, x); if (index == -1) Console.WriteLine("Character not found"); else Console.WriteLine("Last index is " + index); } } /* This code is contributed by vt_m */ PHP <?php // PHP program to find last index of // character x in given string. // Returns last index of // x if it is present. // Else returns -1. function findLastIndex($str, $x) { $index = -1; for ($i = 0; $i < strlen($str); $i++) if ($str[$i] == $x) $index = $i; return $index; } // Driver code // String in which // char is to be found $str = "geeksforgeeks"; // char whose index // is to be found $x = 'e'; $index = findLastIndex($str, $x); if ($index == -1) echo("Character not found"); else echo("Last index is " . $index); // This code is contributed by Ajit. ?> JavaScript <script> // javascript program to find last index // of character x in given string. // Returns last index of x if // it is present Else returns -1. function findLastIndex(str, x) { let index = -1; for (let i = 0; i < str.length; i++) if (str[i] == x) index = i; return index; } // Driver code // String in which char is to be found let str = "geeksforgeeks"; // char whose index is to be found let x = 'e'; let index = findLastIndex(str, x); if (index == -1) document.write("Character not found"); else document.write("Last index is " + index); // This code is contributed by sanjoy_62. </script> OutputLast index is 10 Time Complexity : O(n)Auxiliary Space: O(1) Method 2 (Efficient : Traverse from right): In above method 1, we always traverse complete string. In this method, we can avoid complete traversal in all those cases when x is present. The idea is to traverse from right side and stop as soon as we find character. Implementation: CPP // Simple CPP program to find last index of // character x in given string. #include <iostream> using namespace std; // Returns last index of x if it is present. // Else returns -1. int findLastIndex(string& str, char x) { // Traverse from right for (int i = str.length() - 1; i >= 0; i--) if (str[i] == x) return i; return -1; } // Driver code int main() { string str = "geeksforgeeks"; char x = 'e'; int index = findLastIndex(str, x); if (index == -1) cout << "Character not found"; else cout << "Last index is " << index; return 0; } Java // Java code to find last index // character x in given string. import java.io.*; class GFG { // Returns last index of x if // it is present. Else returns -1. static int findLastIndex(String str, Character x) { // Traverse from right for (int i = str.length() - 1; i >= 0; i--) if (str.charAt(i) == x) return i; return -1; } // Driver code public static void main(String[] args) { String str = "geeksforgeeks"; Character x = 'e'; int index = findLastIndex(str, x); if (index == -1) System.out.println("Character not found"); else System.out.println("Last index is " + index); } } // This code is contributed by Prerna Saini Python3 # Simple Python3 program to find last # index of character x in given string. # Returns last index of x if it is # present. Else returns -1. def findLastIndex(str, x): # Traverse from right for i in range(len(str) - 1, -1,-1): if (str[i] == x): return i return -1 # Driver code str = "geeksforgeeks" x = 'e' index = findLastIndex(str, x) if (index == -1): print("Character not found") else: print("Last index is " ,index) # This code is contributed by Smitha C# // C# code to find last index // character x in given string. using System; class GFG { // Returns last index of x if // it is present. Else returns -1. static int findLastIndex(string str, char x) { // Traverse from right for (int i = str.Length - 1; i >= 0; i--) if (str[i] == x) return i; return -1; } // Driver code public static void Main() { string str = "geeksforgeeks"; char x = 'e'; int index = findLastIndex(str, x); if (index == -1) Console.WriteLine("Character not found"); else Console.WriteLine("Last index is " + index); } } // This code is contributed by vt_m PHP <?php // Simple PHP program to find last index // of character x in given string. // Returns last index of x if it // is present. Else returns -1. function findLastIndex($str, $x) { // Traverse from right for ($i = strlen($str) - 1; $i >= 0; $i--) if ($str[$i] == $x) return $i; return -1; } // Driver code $str = "geeksforgeeks"; $x = 'e'; $index = findLastIndex($str, $x); if ($index == -1) echo("Character not found"); else echo("Last index is " . $index); // This code is contributed by Ajit. ?> JavaScript <script> // Javascript code to find last index character x in given string. // Returns last index of x if // it is present. Else returns -1. function findLastIndex(str, x) { // Traverse from right for (let i = str.length - 1; i >= 0; i--) if (str[i] == x) return i; return -1; } let str = "geeksforgeeks"; let x = 'e'; let index = findLastIndex(str, x); if (index == -1) document.write("Character not found"); else document.write("Last index is " + index); </script> OutputLast index is 10 Time Complexity : O(n) Auxiliary Space: O(1) Comment More infoAdvertise with us Next Article Analysis of Algorithms A Anurag Rawat Improve Article Tags : Misc Strings Searching Technical Scripter DSA +1 More Practice Tags : MiscSearchingStrings Similar Reads Basics & PrerequisitesLogic Building ProblemsLogic building is about creating clear, step-by-step methods to solve problems using simple rules and principles. 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