Matplotlib.axis.Tick.is_transform_set() function in Python

# Implementation of matplotlib function
from matplotlib.axis import Tick
import matplotlib.pyplot as plt  
import numpy as np  
       
# create test data  
np.random.seed(10**7)  
data = [sorted(np.random.normal(0, std, 100))   
       for std in range(1, 4)]  
       
fig, ax1 = plt.subplots()  
val = ax1.violinplot(data) 
   
ax1.set_title("Is artist is explicitly set transform : "
              +str(Tick.is_transform_set(ax1)))  

fig.suptitle('matplotlib.axis.Tick.is_transform_set() \
function Example', fontweight ="bold")  
   
plt.show() 

# Implementation of matplotlib function
from matplotlib.axis import Tick
import matplotlib.pyplot as plt  
import numpy as np  
from matplotlib.patches import Ellipse  
      
    
delta = 15.0
      
angles = np.arange(0, 360 + delta, delta)  
ells = [Ellipse((2, 2), 5, 2, a) for a in angles]  
      
fig, ax = plt.subplots()  
      
for e in ells:  
    Tick.set_clip_box(e, ax.bbox)
    e.set_facecolor("green")
    e.set_alpha(0.05)  
    ax.add_artist(e)  
      
plt.xlim(-1, 5)  
plt.ylim(-1, 5) 
 
ax.set_title("Is artist is explicitly set transform : "
              +str(Tick.is_transform_set(ax)))  

fig.suptitle('matplotlib.axis.Tick.is_transform_set() \
function Example', fontweight ="bold")  
   
plt.show()