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PHP | Imagick displayImage() Function

Last Updated : 10 Jan, 2022
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The Imagick::displayImage() function is an inbuilt function in PHP which is used to displays an image object. Syntax:
bool Imagick::displayImage( $servername )
Parameters: This function accepts a single parameter $servername which is used to specify the server name. Return Value: This function returns True on success. Below programs illustrate the Imagick::displayImage() function in PHP: Program: php
<?php

// Create an Imagick object
$imagick = new Imagick(
'https://media.geeksforgeeks.org/wp-content/uploads/geeksforgeeks-9.png');

// Use displayImage function
$imagick->displayImage(5);

header("Content-Type: image/jpg");

// Display the output image
echo $imagick->getImageBlob();
?>
Output: oil paint image Program 2: php
<?php
$string = "Computer Science portal for Geeks!";

// creating new image of above String 
// and add color and background 
$im = new Imagick();
$draw = new ImagickDraw();

// Fill the color in image 
$draw->setFillColor(new ImagickPixel('green'));

// Set the text font size 
$draw->setFontSize(50);

$matrix = $im->queryFontMetrics($draw, $string);
$draw->annotation(0, 40, $string);
$im->newImage($matrix['textWidth'], $matrix['textHeight'],
         new ImagickPixel('white'));

// Draw the image          
$im->drawImage($draw);

$im->setImageFormat('jpeg');

header("Content-Type: image/jpg");

// Display the output image
echo $im->getImageBlob();
?>
Output: https://media.geeksforgeeks.org/wp-content/uploads/Screenshot-from-2018-10-16-23-23-54-1.png Reference: http://php.net/manual/en/imagick.displayimage.php

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