Python - Append according to Kth character

# Python3 code to demonstrate working of 
# Append according to Kth character
# Using loop

# initializing lists
test_list = ["geeksforgeeks", "best", "for", "geeks"]

# printing string
print("The original list : " + str(test_list))

# initializing K
K = 2 

# initializing N 
N = 'e'

# initializing i, j 
i, j = "**", "##"

res = []
for sub in test_list:
    
    # checking for Kth index to be N
    if sub[K] == N:
        res.append(sub + i)
    else :
        res.append(sub + j)

# Printing the resultant list 
print("The resultant List : " + str(res))

# Python3 code to demonstrate working of 
# Append according to Kth character
# Using list comprehension

# Initializing lists
test_list = ["geeksforgeeks", "best", "for", "geeks"]

# Printing string
print("The original list : " + str(test_list))

# Initializing K
K = 2 

# Initializing N 
N = 'e'

# initializing i, j 
i, j = "**", "##"

# shorthand to solve this problem
res = [sub + i if sub[K] == N else sub + j for sub in test_list]

# Printing results 
print("The resultant List : " + str(res))

# Python3 code to demonstrate working of 
# Append according to Kth character
# Using map() with lambda function

# initializing lists
test_list = ["geeksforgeeks", "best", "for", "geeks"]

# printing string
print("The original list : " + str(test_list))

# initializing K
K = 2 

# initializing N 
N = 'e'

# initializing i, j 
i, j = "**", "##"

# Appending string 
# using map() with lambda function
res = list(map(lambda sub: sub + i if sub[K] == N else sub + j, test_list))

# Printing results 
print("The resultant List : " + str(res))