Python - Remove given character from first element of Tuple
Last Updated :
04 May, 2023
Given a Tuple list, remove K character from 1st element of the Tuple being String.
Input : test_list = [("GF$g!", 5), ("!i$s", 4), ("best!$", 10)], K = '$'
Output : [('GFg!', 5), ('!is', 4), ('best!', 10)]
Explanation : First element's strings K value removed. Input : test_list = [("GF$g!", 5), ("best!$", 10)], K = '$'
Output : [('GFg!', 5), ('best!', 10)]
Explanation : First element's strings K value removed.
Method #1 : Using replace() + list comprehension
In this, we use replace() to perform the task of removing of K character and list comprehension to reform the tuple.
Python3
# Python3 code to demonstrate working of
# Remove K character from first element of Tuple
# Using replace() + list comprehension
# Initializing list
test_list = [("GF ! g !", 5), ("! i ! s", 4), ("best !!", 10)]
# Printing original list
print("The original list is : " + str(test_list))
# Initializing K
K = "!"
# Replace with empty string removes the desired char.
res = [(sub[0].replace(K, ''), sub[1]) for sub in test_list]
# Printing result
print("The filtered tuples : " + str(res))
OutputThe original list is : [('GF!g!', 5), ('!i!s', 4), ('best!!', 10)]
The filtered tuples : [('GFg', 5), ('is', 4), ('best', 10)]
Method #2 : Using translate() + list comprehension
In this, we perform the task of removal using translate(), which needs conversion to ASCII using ord(), and replaced with an empty character.
Python3
# Python3 code to demonstrate working of
# Remove K character from first element of Tuple
# Using translate() + list comprehension
# Initializing list
test_list = [("GF ! g !", 5), ("! i ! s", 4), ("best !!", 10)]
# Printing original list
print("The original list is : " + str(test_list))
# Initializing K
K = "!"
# Translation after conversion to ascii number
res = [(sub[0].translate({ord(K): None}), sub[1]) for sub in test_list]
# Printing result
print("The filtered tuples : " + str(res))
OutputThe original list is : [('GF!g!', 5), ('!i!s', 4), ('best!!', 10)]
The filtered tuples : [('GFg', 5), ('is', 4), ('best', 10)]
Method #3: Using for loop
Python3
# Python3 code to demonstrate working of
# Remove K character from first element of Tuple
# Initializing list
test_list = [("GF!g!", 5), ("!i!s", 4), ("best!!", 10)]
# Printing original list
print("The original list is : " + str(test_list))
# Initializing K
res1 = []
K = "!"
for i in test_list:
res = ""
for j in i[0]:
if(j != K):
res += j
x = (res, i[1])
res1.append(x)
# Printing result
print("The filtered tuples : " + str(res1))
OutputThe original list is : [('GF!g!', 5), ('!i!s', 4), ('best!!', 10)]
The filtered tuples : [('GFg', 5), ('is', 4), ('best', 10)]
Time Complexity: O(N)
Auxiliary Space: O(N)
Method #4 : Using split() and join() methods
Approach:
- Initiate a for loop to traverse the list of tuples.
- Split each first element of a tuple by K and join by an empty string.
- Append the joined string and the second element of the tuple together as a tuple to output list.
- Display output list.
Python3
# Python3 code to demonstrate working of
# Remove K character from first element of Tuple
# Initializing list
test_list = [('GF$g!', 5), ('!i$s', 4), ('best!$', 10)]
# Printing original list
print("The original list is : " + str(test_list))
# Initializing K
K = "$"
# Replacing with empty string removes the desired char.
res = []
for i in test_list:
v = []
x = i[0].split(K)
x = "".join(x)
v.append((x, i[1]))
res.append(v)
# Printing result
print("The filtered tuples : " + str(res))
OutputThe original list is : [('GF$g!', 5), ('!i$s', 4), ('best!$', 10)]
The filtered tuples : [[('GFg!', 5)], [('!is', 4)], [('best!', 10)]]
Time Complexity: O(M*N) M- length of tuples list N - length of each tuple
Auxiliary Space: O(M*N) M- length of tuples list N - length of each tuple
METHOD 5:Using map and lambda method
The given Python code removes a given character from the first element of each tuple in a list using the map function and lambda function. It replaces the given character with an empty string and strips any whitespace from the resulting string.
Algorithm:
- Define a list of tuples test_list.
- Use the map() function with a lambda function to remove the given character from the first element of each tuple.
- The lambda function takes a tuple as input, replaces the given character with an empty string using the replace() method and strips any whitespace from the resulting string using the strip() method.
- The resulting filtered tuples are stored in a list filtered_list.
- The filtered list is printed.
Python3
# Input list
test_list = [("GFg !", 5), ("is", 4), ("best!", 10)]
filtered_list = list(
map(lambda tup: (tup[0].replace('!', '').strip(), tup[1]), test_list))
print("The filtered tuples:", filtered_list)
OutputThe filtered tuples: [('GFg', 5), ('is', 4), ('best', 10)]
Time Complexity: O(N), where n is the number of tuples in the input list. This is because the map() function applies the lambda function to each tuple in the input list once.
Auxiliary Space: O(N), where n is the number of tuples in the input list. This is because the resulting filtered tuples are stored in a list, which has a space complexity of O(n).
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