How to Create an Array of Structs in C?

size of char datatype and char array in C

Last Updated : 15 Oct, 2019

Given a char variable and a char array, the task is to write a program to find the size of this char variable and char array in C. Examples:

Input: ch = 'G', arr[] = {'G', 'F', 'G'}
Output: 
Size of char datatype is: 1 byte
Size of char array is: 3 byte

Input: ch = 'G', arr[] = {'G', 'F'}
Output: 
Size of char datatype is: 1 byte
Size of char array is: 2 byte

Approach: In the below program, to find the size of the char variable and char array:

first, the char variable is defined in charType and the char array in arr.
Then, the size of the char variable is calculated using sizeof() operator.
Then the size of the char array is find by dividing the size of the complete array by the size of the first variable.

Below is the C program to find the size of the char variable and char array:

C

// C program to find the size of
// char data type and char array

#include <stdio.h>

int main()
{

    char charType = 'G';
    char arr[] = { 'G', 'F', 'G' };

    // Calculate and Print
    // the size of charType
    printf("Size of char datatype is: %ld byte\n",
           sizeof(charType));

    // Calculate the size of char array
    size_t size = sizeof(arr) / sizeof(arr[0]);

    // Print the size of char array
    printf("Size of char array is: %ld byte",
           size);

    return 0;
}

Output:

Size of char datatype is: 1 byte
Size of char array is: 3 byte

How to Create an Array of Structs in C?

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