import React, { useEffect } from react;import { BrowserRouter as.pdf

Oct 6, 20230 likes13 views

import React, { useEffect } from 'react'; import { BrowserRouter as Router, Route, Routes, Link, useLocation, Outlet, Navigate } from 'react-router-dom'; // Added useLocation import { App } from './App'; import Cookies from 'js-cookie'; import LoginButton from './authentication/LoginButton'; // Import the LoginButton component import { useAuth0 } from '@auth0/auth0-react'; export default function RouterPage() { useEffect(() => { // Fetch the userId from the Flask backend fetch('http://localhost:5000/callback', { method: 'GET', credentials: 'include', // Important for sending cookies across origins }) .then(response => response.json()) .then(data => { // Assuming the userId is returned in the data object const userId = data.userId; Cookies.set('userId', userId, { expires: 7 }); }) .catch((error) => console.error('Error:', error)); }, []); // These could be different components for your different pages const Title = ({ isAuthenticated }) => ( TasktasticTest Environment {isAuthenticated ? ( Logout ) : ( )} ); return (.

Jordano Food Products Supply Chain Profile Jordano Foods Tracie Shannon, Vice President for Logistics at Jordano Foods (Jordano), had sent the following e-mail to members of the executive committee of the company two years ago: I just returned from a lengthy meeting with Susan Weber, CEO of SAB Distribution. She is under great pressure from her Board of Directors to continue to grow market share and improve profitability. SAB received a recent tender offer from another larger food distributor to buy the company and several members of their board have recommended that the offer be seriously considered. Susan feels that SAB can continue to improve their bottom line with additional changes in service offerings. Ms. Weber met with SABs major suppliers and customers to discuss new services that SAB can offer to enhance the competitiveness of the SAB supply chain. She was particularly concerned with the changing demographics of their customer base, particularly the Gen-Y and Plus-55 age groups. Background on Jordano Foods Jordano Foods was founded in 1950 in Lewistown, Pennsylvania, by two brothers, Luigi and Mario Jordano. Their parents operated a restaurant in Burnham, Pennsylvania, featuring Italian cuisine. Marie Jordano was famous for her culinary skills. She developed her own recipes for pasta sauce, meatballs, fresh and dry pasta, and other Italian food items. Luigi and Mario worked in a restaurant prior to establishing Jordano Foods. The brothers felt that they could capitalize on the family recipes by selling pasta, sauces, and other related Italian food products to restaurants in nearby communities in central Pennsylvania. Their initial venture was so successful that they expanded their product line and began selling their products to small and medium-sized wholesalers and distributors throughout Pennsylvania. They built a plant in Lewistown to produce their food products and subsequently built another plant in Elizabethtown, Pennsylvania, and a warehouse in Mechanicsburg, Pennsylvania. Current Situation The 1990s and 2000s were times of significant growth for Jordano. Mario and Luigi were still active in the company as president/CEO and chairman of the board, respectively. Revenue now exceeded $600 million per year, and a third plant had been built in the western part of Pennsylvania near Uniontown. A group of professional managers has been developed in the company to head up the major functional areas. Tracie Shannon was hired in 2010 to manage the logistics area which had not received much attention. Tracie realized that the Jordano brothers had managed and developed the manufacturing and marketing functions during the formative years, and these two areas had been considered as cornerstones of the companys success. Logistics was a relatively new functional area for Jordano, but had received more attention with Tracies vision and leadership. The vision of Susan Weber for SAB had tremendous potential for all members of their supply chain.

Java Code The traditional way to deal with these in Parsers is the .pdfstopgolook

Java Code: The traditional way to deal with these in Parsers is the Expression-Term-Factor pattern: Expression: TERM {+|- TERM} Term: FACTOR {*|/ FACTOR} Factor: number | ( EXPRESSION ) A couple of notation comments: | means "or" - either + or -, either * or / {} means an optional repeat. That's what allows this to parse 1+2+3+4 Think of these as functions. Every CAPTIALIZED word is a function call. Consider our meme expression above: 6/2*(1+2) We will start by looking at expression. Expression starts with a TERM. We can't do anything until we resolve TERM, so let's go there. A term starts with FACTOR. Again, we can't do anything until we deal with that. A factor is a number or a (EXPRESSION). Now we can look at our token (hint: MatchAndRemove). We see a number. OK - our factor is a number. We "return" that. Remember that we got to factor from term. Let's substitute our number in: TERM: FACTOR(6) {*|/ FACTOR} Now we deal with our optional pattern. Is the next character * or /? Yes! Now is the next thing a factor? It turns out that it is. Let's substitute that in: TERM: FACTOR(6) / FACTOR(2) But remember that our pattern is a REPEATING pattern (hint: loop): TERM: FACTOR(6) / FACTOR(2) {*|/ FACTOR} We see the * and call factor. But this time, the factor is not a number but a parenthetical expression. Factor: number | ( EXPRESSION ) Factor calls expression. Expression calls term, term calls factor, factor returns the number 1. Term doesn't see a * or / so it passes the 1 up. Expression sees the + and calls term. Term calls factor which returns the 2. Expression doesn't see a +|- value so ends the loop and returns 1+2. So, remember that we were here: TERM: FACTOR(6) / FACTOR(2) * FACTOR Our factor is (1+2). That can't be broken down. That math HAS to be done before can multiply or divide. That's what enforces order of operations. In code, this looks like something like this (pseudo-code): Node Factor() num = matchAndRemove(NUMBER) if (num.isPresent) return num if (matchAndRemove(LPAREN).isPresent) exp = Expression() if (exp == null) throw new Exception() if (matchAndRemove(RPAREN).isEmpty) throw new Exception() Node Term() left = Factor() do op = MatchAndRemove(TIMES) if (op.isEmpty) op=MatchAndRemove(DIVIDE) if (op.isEmpty) return left right = Factor() left = MathOpNode(left, op, right) while (true) Node Expression() left = Term() do op = MatchAndRemove(PLUS) if (op.isEmpty) op=MatchAndRemove(MINUS) if (op.isEmpty) return left right = Term() left = MathOpNode(left, op, right) while (true) What is this "MathOpNode"? It's "just" a new node type that holds two other nodes (left and right) and an operation type: *, /, +, -. Notice that the loops use the result of one operation as the left side of the next operation. This is called left associative - the left most part is done first. Right associativity is the opposite - the rightmost part is done first, then we work our way left. Generally, notice the pattern here - we call a function that is the lo.

Javai have to make a method that takes a linked list and then retu.pdfstopgolook

Java i have to make a method that takes a linked list and then returns a new linked list that is the reverse of the original this is the starting code /** * LinkedList lab. * @author Emma Cheney * @version 10/2/23 */ public class LinkedList { /** * Internal Node class used for the linked list. */ public class Node { String key; int value; Node next; /** * Node Constructor. * @param key The Key * @param value The Value */ public Node(String key, int value) { this.key = key; this.value = value; } } private Node head; private Node tail; /** * The default constructor. */ public LinkedList() { head = null; tail = null; } /** * Add the key, value pair to the head of the linkedlist. * @param key The Key * @param val The Value * */ public void addHead(String key, int val) { Node n = new Node(key, val); if (head == null) { head = n; tail = n; } else { n.next = head; head = n; } } /** * Add the key, val pair to the tail of the linkedlist. * @param key The Key * @param val The Value */ public void addTail(String key, int val) { Node n = new Node(key, val); if (tail == null) { head = n; tail = n; } else { tail.next = n; tail = n; } } /** * Returns the String format of the linkedlist. * @return String The String format. */ public String toString() { String ret = ""; Node curr = head; while (curr != null) { if (curr.next != null) { ret += curr.key + ":" + curr.value + ", "; } else { ret += curr.key + ":" + curr.value; } curr = curr.next; } return ret; } /** * Locate the Node in the linkedlist with the given key. * @param key The key to find in the LinkedList * @return Node Returns the Node with the given key or null if non-existent. */ private Node find(String key) { Node curr = head; while (curr != null) { if (curr.key.equals(key)) { return curr; } curr = curr.next; } return null; } A static method called reversed that takes a LinkedList as a parameter and returns a new LinkedList that is reversed. f; traverse through the input list (starting at the head). In order to reverse the ordering, you need to add the current node's key and value onto the head of the new list (addHead method). Do not change the input list or any values in it. Example (result in red) //assumelistcontainsthesekeysandvalues://ie:6,bi:48,bi:73,bi:63LinkedList.reversed(list);bi:63,bi: 73,bi:48,ie:6.

J.M. Baker worked as a traditional land use researcher and consultan.pdfstopgolook

J.M. Baker worked as a traditional land use researcher and consultant for seven years between her MA and PhD degrees in Anthropology, and she continues to occasionally assist First Nations in the traditional land use research and consultation process. During the summers of 2008 and 2009 she worked for the Bigstone Cree Nation in northern Alberta as a consultant performing traditional land use research and assessments. One particular oil and gas company with a large oil sands lease was proposing a pilot project to develop technology to extract dicult to reach in situ deposits of bitumen and so approached Bigstone Cree Nation to complete a traditional land use assessment. At the time, [Company Xs] activities were top secret: they held a smaller start- up company with a dierent name, they were extremely paranoid about Chinese spies, and the very trappers they were consulting were not allowed to know anything about what [Company X] was doing or exactly where they were doing it. Baker was working with Bigstone Cree Nation members mostly from the remote community of Chipewyan Lake, whose hunting and trapping areas are within the companys lease. Several Bigstone Cree Nation members and Baker spent most of that summer visiting important hunting, trapping, shing, camping, and plant and medicine gathering places within Bigstone Cree Nation territory. They walked a once well-worn trail from Chipewyan Lake to the Wabasca River that took several days. On one of the nal days, they crossed the new road to Chipewyan Lake and encountered the startling noise of construction transforming it into an all-weather road for industrial use. They noticed that after having spent days with the subtler sounds of the boreal forest, the construction sounds were startling, alarming, and even stress-inducing. The trappers in the group explained that this kind of noise pollution also aects animal movements. At rst it scares away animals; then in time animals such as moose start to come back, but predators like wolves have an advantage over them because the moose can no longer hear them approaching. Additionally, roads create corridors that change animal movements (Brody 2004[1981]) and further act to open up the landscape. When Baker submitted the traditional land use report to the [Company X], they claimed there is no scientic evidence proving noise aects animals and in fact there are studies on domestic sheep from the UK that show that noise from trac has no impact on animals. [Company X] had also hired a social science and health research rm to look at capacity building, income, and health in the small community of Chipewyan Lake. Baker sat in on one of their meetings. The consultants ew up to Wabasca and back in the same day in a chartered plane from Calgary and asked a couple of representatives from Chipewyan Lake, in a local Wabasca restaurant, about what kind of research they could do and whether or not people ate wild meat or had jobs. Baker felt uncomfortable for eve.

IT Project Management homework Identify any project of your choice.pdfstopgolook

IT Project Management homework Identify any project of your choice and answer the questions in that follow: NB: Only IT projects based on the design and development of systems/applications will be accepted. 1.1 With regards to identifying and selecting projects: a. Briefly explain the IT project selected then discuss any two (2) factors relevant when developing a selection criterion for the project. b. An RFP may include evaluation criteria. Discuss why this would be required, in relation to the IT project chosen. 1.2 With regards to developing project proposals: c. Discuss the importance of each section of a proposal and include one element to include under each section in relation to the chosen IT project. d. Discuss four (4) important contract terms and conditions to include in the IT projects contract..

INSTRUCTIONSDevelop, and present a plan and business case for an a.pdfstopgolook

INSTRUCTIONS Develop, and present a plan and business case for an asset management development for the UNIVERSITY OF CAPE TOWN. The report may represent a project proposal or may extend into implementation and assessment of results. The scale of this and the degree of detail may vary depending on the type of development, which can be a minor improvement proposal or a more significant acquisition or development. Typical features to be contained in your report are shown in the Business Case Outline as shown in the following section. However, the range of items and level of detail covered in your report should reflect the actual range and relevance of the activity in your project. 8. Project financial analysis for preferred option a) Added revenue, value, and/or cost savings b) Acquisition and development costs c) Net personnel and operating costs or savings d) Logistic support and through life costs, LCC e) Project implementation costs f) Required budget g) Cash flow analysis h) Investment analysis: Payback Period i) Investment analysis, NPV, IRR (indicate planning horizon) 9. Semi-quantifiable benefits. Estimate physical values, e.g., extra tonnes produced, reduction in losses. Possibly estimate ZAR value but state basis of calculation so that management judgement can be applied. Benefits may include: a) Increased reliability and availability b) Reduced production loss c) Asset life extension d) Human resource factors, availability, net cost, and training 10. Environmental assessment a) Environmental protection actions required, such as sound barriers and waste disposal facilities b) Environmental benefits and regulatory requirements met 11. Health and safety assessment and requirements or issues 12. Nonfinancial benefits a) Identify benefits of a nonfinancial nature such as social services, sports ground development, 13. Summary of project activities a) Acquisition/Development strategy b) Scope of Work c) Timings, Project lead time d) Business continuity plan during implementation e) Sustainability aspects 14. Risk analysis a) Identify risks of doing nothing b) Identify risks to the project succeeding, solution risk, schedule risk, and financial risk. May include high, medium, and low analysis c) Identify risks in the longer term 15. Development project management a) Indicate the resources and funds required to manage the implementation of the plan 16. Performance monitoring a) Indicate how the intended results will be monitored and reported b) Identify the key measure of success 17. Proposed date of decision 18. Proposed in-service date 19. Concluding summary..

In the realm of professional dynamics, understanding and appreciating .pdfstopgolook

In the realm of professional dynamics, understanding and appreciating the diverse array of personalities is essential for fostering a productive and harmonious work environment. Human beings are distinctly wired with varying degrees of extroversion, introversion, or ambiversion, each imprinting a unique pattern of traits and abilities that influence their contributions within a workplace. Extroverts thrive in social settings, exuding confidence and enthusiasm. Introverts, on the other hand, derive their strength from introspection and solitude. Ambiverts, embodying a blend of extroverted and introverted traits, can adapt flexibly to different situations. In my experience, I've worked closely with an extroverted colleague named Daniel. His vibrant personali.

In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdfstopgolook

In C++ please, do not alter node.h Step 1: Inspect the Node.h file Inspect the class declaration for a doubly-linked list node in Node.h. The Node class has three member variables: a double data value, a pointer to the next node, and a pointer to the previous node. Each member variable is protected. So code outside of the class must use the provided getter and setter member functions to get or set a member variable. Node.h is read only, since no changes are required. Step 2: Implement the Insert() member function A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's Insert() member function. The function must create a new node with the parameter value, then insert the node into the proper sorted position in the linked list. Ex: Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList. The list is displayed after each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove() member function Implement the SortedNumberList class's Remove() member function. The function takes a parameter for the number to be removed from the list. If the number does not exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the number is removed from the list and true is returned. Uncomment the commented-out part in main() that reads a second input line and removes numbers from the list. Test in develop mode to ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84 List after removing 84: 61 72 Code below: main.cpp #include #include #include #include "Node.h" #include "SortedNumberList.h" using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source); int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin, inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value and show the sorted list's contents after each insertion SortedNumberList list; for (auto term : terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl; list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin, inputLine); terms = Space.

Im trying to define a class in java but I seem to be having a bit o.pdfstopgolook

I'm trying to define a class in java but I seem to be having a bit of trouble. What do I do from here? package CompanyManagementSystem; 1/ TODO: You need to define the class for Employee // class Employee \{ String name, title, department; int birthYear, entryYear; String[] skills, cwp; int points; \} "Name": "ACE Company", "Year": "2001", "CEO": "Ontaria Laker", "Number of Departments": 6, "Number of Employees": 7, "Departments": [ \{ "Name": "John Parker", "Title": "Engineer", "Birth Year": 1992, "Entry Year": 2015, "Department": "Mobile", "Skills": ["Graphics"], "CWP": ["ACE App"], "Points": 230 \},\{ "Name": "David Collins", "Title": "Manager", "Birth Year": 1988, "Entry Year": 2012, "Department": "Mobile", "Skills": ["Web Design"], "CWP": ["ACE App"], "Points": 620 \},\{.

in c languageTo determine the maximum string length, we need to .pdfstopgolook

in c language To determine the maximum string length, we need to create a new callback function that utilizes an alternative user data structure. This callback function should adhere to the same format as demonstrated in the example. The data provided to our callback consists of: A node containing the node->data pointer, which will store our string. A userdata argument, represented as (void *), capable of holding any desired content. We possess complete control over the content at this pointer location, as it will be whatever value we have passed. Consequently, we can: Establish a structure to store any pertinent values we require. Transmit the address of this structure into the function. use this code and just add your code where it says TO DO #include #include #include #include #include "LLGeneric.h" /** define the maximum length of a line that we can read */ #defineLINE_BUFFER_SIZE1024 /** * We can use this as our "user data" to help us calculate the maximum * length string * * Add anything else to this structure that you wish */ struct maxData { size_t maxLenSoFar; char *maxStringSoFar; }; /** * our "user function" or "callback" for printing. * * We know what "void *userdata" is going to be because it is * simply what we pass in at the call below, so it is safe to * cast back to a FILE * as that is what we passed it. * * This is called a "callback" as it "call back into" our own * code from within a generic routine. */ int myFindLongestStringNode(GenericListNode *node, int index, void *userdata) { /** * Add more code here. You will need to: * - convert the GenericListNode payload in the field "data" to your * known (char *) type * - conver the (void *) userdata into your known (struct maxData *) * type * - use the fact that you can examine and store the values provided * through the userdata to see what has been calculated by earlier * calls to this function and update based on what you see here, * in order to determine what the longest string is in the whole * set of nodes. */ return 1; } int doListActivities(GenericListNode *list) { /** create an instance of our structure for use as the user data */ struct maxData maxDataWorkingStruct; int nProcessed = 0; /** initialize our structure -- if you added fields, set them up here */ maxDataWorkingStruct.maxLenSoFar = 0; maxDataWorkingStruct.maxStringSoFar = NULL; /** * TO DO: Iterate using the callback, which should calculate what * the longest string in the list is */ nProcessed = lstPerformIterativeAction( list, /* pointer to the first list node */ myFindLongestStringNode, /* pointer to our function */ (void *) &maxDataWorkingStruct); /** print out the result */ printf("The longest string has %ld characters\n", maxDataWorkingStruct.maxLenSoFar); printf("The longest string is: %s\n", maxDataWorkingStruct.maxStringSoFar); return nProcessed; } /** **Tools provided below here you won't need to edit -- they **simply process the command line, and load and free the **generic linked list and the st.

In 2011, the head of the Presidential Protection Force (for purposes.pdfstopgolook

In 2011, the head of the Presidential Protection Force (for purposes of this assignment, we will call him Mr. Cruise) contacted various providers expected to have a presence at the SHOT Show. Mr. Cruise presented the right credentials and indicated that he was interested in outfitting his unit with new tactical gear and weapons, from head to toe. Many companies were excited at the prospect of securing a contract with the Gabonese Presidential Force and looked forward to meeting Mr. Cruise at the SHOT Show. How did people respond? At the SHOT Show, all of these individuals and others were arrested by Mr. Cruise (who happened to be a Special Agent) and the FBI. - Assignment: You are a newly hired Assistant United States Attorney for the District of Nevada. The US Attorney has asked you, in light of Mr. Cruise's work to evaluate to what extent charges should be filed against the individuals identified above at Company A through Company E as well as the companies themselves. Focusing exclusively on the Foreign Corrupt Practices Act (see page 232 of your textbook for details), please prepare a brief two to three page memorandum to the US Attorney with your recommendations. Your memorandum should follow the following format: Introduction Brief Summary of FCPA Factual Background Analysis Recommendation. Do not use IRAC. There is no special formula other than what is presented above. Some key facts for you to keep in mind:.

import java.util.Scanner;public class Main {private static i.pdfstopgolook

import java.util.Scanner; public class Main { private static int n; private static int[] referenceString; private static int[] physicalFrames; private static int[] victimPages; private static int pageFaults; public static void main(String[] args) { Scanner input = new Scanner(System.in); int choice; do { System.out.println("0 Exit"); System.out.println("1 Input N"); System.out.println("2 Input the reference string"); System.out.println("3 Simulate the OPT algorithm"); System.out.println("4 Simulate the NEW algorithm"); System.out.print("Select option: "); choice = input.nextInt(); switch (choice) { case 0: System.out.println("Exiting the program..."); break; case 1: System.out.print("Enter the value of N (2-8): "); n = input.nextInt(); if (n < 2 || n > 8) { System.out.println("Invalid value of N!"); n = 0; } else { physicalFrames = new int[n]; victimPages = new int[n]; System.out.println("N set to " + n + "."); } break; case 2: if (n == 0) { System.out.println("Please enter the value of N first!"); } else { System.out.print("Enter the reference string (length at least " + n + ", max length 20): "); String[] strArr = input.next().split(""); int len = strArr.length; if (len < n || len > 20) { System.out.println("Invalid length of reference string!"); } else { referenceString = new int[len]; for (int i = 0; i < len; i++) { int page = Integer.parseInt(strArr[i]); if (page < 0 || page > 9) { System.out.println("Invalid page number!"); referenceString = null; break; } referenceString[i] = page; } if (referenceString != null) { System.out.println("Reference string set to " + input.next() + "."); } } } break; case 3: if (n == 0) { System.out.println("Please enter the value of N first!"); } else if (referenceString == null) { System.out.println("Please enter the reference string first!"); } else { System.out.println("Simulating the OPT algorithm..."); simulateOPT(); } break; case 4: if (n == 0) { System.out.println("Please enter the value of N first!"); } else if (referenceString == null) { System.out.println("Please enter the reference string first!"); } else { System.out.println("Simulating the NEW algorithm..."); simulateNEW(); } break; default: System.out.println("Invalid choice!"); break; } System.out.println(); } while (choice != 0); } private static void simulateOPT() { pageFaults = 0; int len = referenceString.length; System.out.println("Reference String\tPhysical Frames\tPage Faults\tVictim Pages"); for (int i = 0; i < len; i++) { int page = referenceString[i]; boolean found = false; for (int j = 0; j < n; j++) { if (physicalFrames[j] == page) { found = true; break; } } if (!found) { pageFaults++; int maxDist = 0; int victimPage = -1; for (int j = 0; j < n; j++) { int dist = 0; for (int k = i + 1; k < len; k++) { dist++; if (physicalFrames[j] == referenceString[k]) { break; } } if (dist > maxDist) { maxDist = dist; victimPage = j; } } physicalFrames[victimPage] = page; victimPages[i] = physicalFrames[victimPage]; } else { victimPages[i] = -1;.

If a taxpayer has investment income that exceeds a certain threshold.pdfstopgolook

If a taxpayer has investment income that exceeds a certain threshold, they are not eligible to claim the Earned Income Credit. For 2022, what is that threshold? If a taxpayer's Earned Income Credit (EIC) was disallowed, what additional step must the taxpayer take the next time they claim the EIC? Stan would like to claim his grandson, Spencer, as his qualifying child so he can claim the Earned Income Credit (EIC). However, Spencer's mother, Alma, is also eligible to claim Spencer as her qualifying child for EIC purposes. As Stan's tax preparer, what information would you share with Stan? All of the following statements regarding the 2022 Additional Child Tax Credit are correct, EXCEPT? Paloma (63) shared a home all year with her son, Antonio (41), and Antonio's son, Danny (23). They were all U.S. citizens, lived in the U.S. all year, and all had social security numbers valid for employment. Paloma and Antonio worked full-time. Danny was a part-time student during the year; he took one class at the local community college. Danny also worked part-time and had wages of $6,800. No one else lived in the home. Paloma had earned income and an adjusted gross income of $23,459. She had no foreign income or investment income. Antonio had earned income and an adjusted gross income of $32,500. He had no foreign income or investment income. Who, if anyone, is eligible to claim and receive the Earned Income Credit? Which of the following taxpayers qualifies for the Earned Income Credit? (All are U.S. citizens, lived in the United States for more than six months, and have valid social security numbers that allow them to work. They did not have any foreign income and will not file Form 2555, Foreign Earned Income.).

Im having an issue with the simulateOPT() methodthis is the p.pdfstopgolook

I'm having an issue with the simulateOPT() method this is the purpose: this is my code: import java.util.Scanner; public class Main { private static int n; private static int[] referenceString; private static int[] physicalFrames; private static int[] victimPages; private static int pageFaults; public static void main(String[] args) { Scanner input = new Scanner(System.in); int choice; do { System.out.println("0 - Exit"); System.out.println("1 - Input N"); System.out.println("2 - Input the reference string"); System.out.println("3 - Simulate the OPT algorithm"); System.out.println("4 - Simulate the NEW algorithm"); System.out.print("Select option: "); choice = input.nextInt(); switch (choice) { case 0: System.out.println("Exiting the program..."); break; case 1: System.out.print("Enter the value of N (2-8): "); n = input.nextInt(); if (n < 2 || n > 8) { System.out.println("Invalid value of N!"); n = 0; } else { physicalFrames = new int[n]; victimPages = new int[n]; System.out.println("N set to " + n + "."); } break; case 2: if (n == 0) { System.out.println("Please enter the value of N first!"); } else { System.out.print("Enter the reference string (length at least " + n + ", max length 20): "); String[] strArr = input.next().split(""); int len = strArr.length; if (len < n || len > 20) { System.out.println("Invalid length of reference string!"); } else { referenceString = new int[len]; for (int i = 0; i < len; i++) { int page = Integer.parseInt(strArr[i]); if (page < 0 || page > 9) { System.out.println("Invalid page number!"); referenceString = null; break; } referenceString[i] = page; } if (referenceString != null) { System.out.println("Reference string set to " + String.join("", strArr) + "."); } } } break; case 3: if (n == 0) { System.out.println("Please enter the value of N first!"); } else if (referenceString == null) { System.out.println("Please enter the reference string first!"); } else { System.out.println("Simulating the OPT algorithm..."); simulateOPT(); } break; case 4: if (n == 0) { System.out.println("Please enter the value of N first!"); } else if (referenceString == null) { System.out.println("Please enter the reference string first!"); } else { System.out.println("Simulating the NEW algorithm..."); simulateNEW(); } break; default: System.out.println("Invalid choice!"); break; } System.out.println(); } while (choice != 0); } private static void simulateOPT() { pageFaults = 0; int len = referenceString.length; System.out.println("Reference String\tPhysical Frames\tPage Faults\tVictim Pages"); for (int i = 0; i < len; i++) { int page = referenceString[i]; boolean found = false; for (int j = 0; j < n; j++) { if (physicalFrames[j] == page) { found = true; break; } } if (!found) { pageFaults++; int maxDist = 0; int victimPage = -1; for (int j = 0; j < n; j++) { int dist = 0; for (int k = i + 1; k < len; k++) { dist++; if (physicalFrames[j] == referenceString[k]) { break; } } if (dist > maxDist) { maxDist = dist; victimPage = j; } } .

I. Naive Robot Navigation ProblemDesign a program that uses the B.pdfstopgolook

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