LEAST COST METHOD
- 1. LEAST COST METHOD BY VISHAL HOTCHANDANI ROLL NO 60
- 2. TRANPORTATION PROBLEM (BALANCED) USES OF LEAST COST METHOD LEAST COST METHOD TRANPORTATION PROBLEM( UNBALANCED) Table of Contents
- 3. Destination constraints:Cost As A Priority Solve the Problem Supply constraints: Constraints LEAST COST METHOD
- 4. 1 FINANCIAL ANALYSIS 2 ECONOMIC ANALYSIS 3 RISK ASSESSMENT 4 TRANPORTATION 5 ENVIRONMENT WHERE LEAST COST METHOD IS USED
- 5. TRANSPORTATION PROBLEM WITH BALANCED SITUATIONS ASSUMING THEM INDUSTRIES ASSUMING THEM STORES BALANCED COST
- 6. 1 The minimum cost in the matrix is Rs 3, but there is a tie in the cell BF, and CD, now the question arises in which cell we shall allocate. Generally, the cost where maximum quantity can be assigned should be chosen to obtain the better initial solution. Therefore, 35 units shall be assigned to the cell BF.
- 7. 5 Again the minimum cost in the matrix is Rs 3. Therefore, 20 units shall be assigned to the cell CD. With this, the demand of retailer D gets fulfilled. Only 40 units are left with the source C.
- 8. 40 The next minimum cost is 8, assign 50 units to the cell AE. The supply of source A gets saturated. The next minimum cost is Rs 9; we shall assign 40 units to the cell CE. With his both the demand and supply of all the sources and origins gets saturated.
- 9. Total Cost = 50*8 + 5*6 + 35*3 +20*3 +40*9 = Rs 955. The total cost can be calculated by multiplying the assigned quantity with the concerned cost of the cell. Therefore,
- 10. Example of Unbalanced Transportation Problem Plant Warehouse Supply W1 W2 W3 A 28 17 26 500 B 19 12 16 300 Demand 250 250 500 The total demand is 1000, whereas the total supply is 800. Si<Dj Total supply < total demand.
- 11. Plant Warehouse Supply W1 W2 W3 A 28 17 26 500 B 19 12 16 300 Unsatisfied demand 0 0 0 200 Demand 250 250 500 1000
- 12. Plant Warehouse Supply W1 W2 W3 A 28 17 26 500 B 19 12 16 300 Unsatisfied demand 0 0 0 200 Demand 250 250 500 1000 200 250 50 50 450