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This document provides an overview of hands-on lab demonstrating MySQL installation, configuration, administration and basic usage. It outlines installing MySQL, setting passwords and users, creating databases and tables, loading sample data, and performing queries. It also covers more advanced topics like triggers, stored procedures, transactions and exporting data. The lab is intended to familiarize users with common MySQL tasks and functions through a guided tutorial example.

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<Insert Picture Here> MySQL: Regis Hands On Lab Keith Larson keith.larson@oracle.com MySQL Community Manager
The following is intended to outline our general product direction. It is intended for information purposes only, and may not be incorporated into any contract. It is not a commitment to deliver any material, code, or functionality, and should not be relied upon in making purchasing decisions. The development, release, and timing of any features or functionality described for Oracle’s products remains at the sole discretion of Oracle. Safe Harbor Statement
tar -xvf MySQL-5.5.16-1.rhel5.x86_64.tar rpm -i MySQL-server-5.5.16-1.rhel5.x86_64.rpm It will prompt you with setting passwords but I will show that soon. MySQL Installation
http://dev.mysql.com/doc/index-other.html wget http://downloads.mysql.com/docs/world_innodb.sql.gz wget launchpad.net/test-db/employees-db-1/1.0.6/+download/ employees_db-dump-files-1.0.5.tar.bz2 MySQL Test Data
-bash-3.2$ mysql mysql> create database world; ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'world' mysql> exit mysql -u root mysql> CREATE DATABASE world; mysql>exit; mysql -u root world < world_innodb.sql MySQL Denied
-bash-3.2$ mysqladmin -u root password brad -bash-3.2$ mysql -u root world ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) -bash-3.2$ mysql -u root world -p Enter password: MySQL Set Root Password
http://dev.mysql.com/doc/refman/5.5/en/grant.html mysql> CREATE USER 'monty'@'localhost' IDENTIFIED BY 'some_pass'; mysql> GRANT ALTER, CREATE VIEW, CREATE, DELETE, DROP, GRANT OPTION, INDEX, INSERT, SELECT, SHOW VIEW, TRIGGER, UPDATE ON *.* TO 'monty'@'localhost' WITH GRANT OPTION; mysql> CREATE USER 'monty'@'%' IDENTIFIED BY 'some_pass'; mysql> GRANT ALTER, CREATE VIEW, CREATE, DELETE, DROP, GRANT OPTION, INDEX, INSERT, SELECT, SHOW VIEW, TRIGGER, UPDATE ON *.* TO 'monty'@'%' WITH GRANT OPTION; mysql> flush privileges ; MySQL New Users
http://dev.mysql.com/doc/refman/5.5/en/grant.html mysql> CREATE USER 'admin'@'localhost' IDENTIFIED BY 'admin_pass'; GRANT ALL ON *.* TO 'admin'@'localhost'; mysql> flush privileges ; mysql -u monty -p Enter password: mysql -u admin -p Enter password: MySQL New Super Users
mysql -u admin -p mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | bobmason | | mysql | | performance_schema | | test | | world | +--------------------+ mysql> create database <yourname>_example; Query OK, 1 row affected (0.00 sec) MySQL Create Database/Schema
mysql> use world; mysql> show tables; +-----------------+ | Tables_in_world | +-----------------+ | City | | Country | | CountryLanguage | +-----------------+ 3 rows in set (0.00 sec) mysql> show create table City; MySQL Table
CREATE TABLE `City` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Name` char(35) NOT NULL DEFAULT '', `CountryCode` char(3) NOT NULL DEFAULT '', `District` char(20) NOT NULL DEFAULT '', `Population` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`), KEY `CountryCode` (`CountryCode`), CONSTRAINT `city_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) ) ENGINE=InnoDB AUTO_INCREMENT=4080 DEFAULT CHARSET=latin1 MySQL Table City
mysql> use <yourname>_example; mysql> CREATE TABLE `City` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Name` char(35) NOT NULL DEFAULT '', `CountryCode` char(3) NOT NULL DEFAULT '', `District` char(20) NOT NULL DEFAULT '', `Population` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`), KEY `CountryCode` (`CountryCode`), CONSTRAINT `city_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) ) ENGINE=InnoDB ERROR 1005 (HY000): Can't create table '<yourname>_example.City' (errno: 150) http://forums.mysql.com/read.php?22,19755,19755 MySQL Create Table in Your Database
mysql> show create table world.Country; mysql> CREATE TABLE `Country` ( -> `Code` char(3) NOT NULL DEFAULT '', -> `Name` char(52) NOT NULL DEFAULT '', -> `Continent` enum('Asia','Europe','North America','Africa','Oceania','Antarctica','South America') NOT NULL DEFAULT 'Asia', -> `Region` char(26) NOT NULL DEFAULT '', -> `SurfaceArea` float(10,2) NOT NULL DEFAULT '0.00', -> `IndepYear` smallint(6) DEFAULT NULL, -> `Population` int(11) NOT NULL DEFAULT '0', -> `LifeExpectancy` float(3,1) DEFAULT NULL, -> `GNP` float(10,2) DEFAULT NULL, -> `GNPOld` float(10,2) DEFAULT NULL, -> `LocalName` char(45) NOT NULL DEFAULT '', -> `GovernmentForm` char(45) NOT NULL DEFAULT '', -> `HeadOfState` char(60) DEFAULT NULL, -> `Capital` int(11) DEFAULT NULL, -> `Code2` char(2) NOT NULL DEFAULT '', -> PRIMARY KEY (`Code`) -> ) ENGINE=InnoDB; Query OK, 0 rows affected (0.02 sec) MySQL Try again ….
Mysql> CREATE TABLE `City` ( -> `ID` int(11) NOT NULL AUTO_INCREMENT, -> `Name` char(35) NOT NULL DEFAULT '', -> `CountryCode` char(3) NOT NULL DEFAULT '', -> `District` char(20) NOT NULL DEFAULT '', -> `Population` int(11) NOT NULL DEFAULT '0', -> PRIMARY KEY (`ID`), -> KEY `CountryCode` (`CountryCode`), -> CONSTRAINT `city_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) -> ) ENGINE=InnoDB; Query OK, 0 rows affected (0.04 sec) MySQL City works now...
Mysql> CREATE TABLE `CountryLanguage` ( `CountryCode` char(3) NOT NULL DEFAULT '', `Language` char(30) NOT NULL DEFAULT '', `IsOfficial` enum('T','F') NOT NULL DEFAULT 'F', `Percentage` float(4,1) NOT NULL DEFAULT '0.0', PRIMARY KEY (`CountryCode`,`Language`), KEY `CountryCode` (`CountryCode`), CONSTRAINT `countryLanguage_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) ) ENGINE=InnoDB MySQL CountryLanguage as well..
mysql> use <yourname>_example; mysql> insert into Country select * from world.Country; Query OK, 239 rows affected (0.03 sec) Records: 239 Duplicates: 0 Warnings: 0 mysql> insert into CountryLanguage select * from world.CountryLanguage; Query OK, 984 rows affected (0.03 sec) Records: 984 Duplicates: 0 Warnings: 0 mysql> insert into City select * from world.City; Query OK, 4079 rows affected (0.29 sec) Records: 4079 Duplicates: 0 Warnings: 0 Faster -- mysql -u admin -p <yourname>_example < world_innodb.sql MySQL Add Data
SELECT ID , Name , CountryCode , Population FROM City WHERE CountryCode = 'USA' ORDER BY Population DESC limit 20; SELECT C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' ORDER BY C.Population DESC limit 20; MySQL Look at some data
mysql> SELECT C.ID , C.Name , C.CountryCode , C.Population -> FROM City C -> INNER JOIN Country Y ON Y.Code = C.CountryCode -> INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode -> WHERE Y.Code = 'USA' -> ORDER BY Population DESC -> GROUP BY C.Name limit 20; MySQL Group by…
mysql> SELECT C.ID , C.Name , C.CountryCode , C.Population -> FROM City C -> INNER JOIN Country Y ON Y.Code = C.CountryCode -> INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode -> WHERE Y.Code = 'USA' -> ORDER BY Population DESC -> GROUP BY C.Name limit 20; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP BY C.Name limit 20' at line 7 mysql> MySQL Group by…Error
SELECT C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' GROUP BY C.Name ORDER BY Population DESC limit 20; MySQL Error fixed
SET @RANK=0; # Variable SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' GROUP BY C.Name ORDER BY Population DESC limit 20; MySQL Rank Results
SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' UNION SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.name = 'Denver' GROUP BY C.Name ORDER BY Population DESC limit 25; MySQL Union Example
SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' UNION SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.name = 'Denver' GROUP BY C.Name ORDER BY Population DESC limit 25; ## Not what you wanted is it.... MySQL Union Example
SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , DISTINCT(C.Name) as Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.Population >= 3694820 UNION SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.name = 'Denver' GROUP BY C.Name ORDER BY Population DESC limit 25; MySQL Union Example
SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' GROUP BY C.Name ORDER BY Population DESC limit 100 INTO OUTFILE '/tmp/mysql_export.csv' FIELDS TERMINATED BY ',' LINES TERMINATED BY 'n' MySQL Export Example
http://dev.mysql.com/doc/refman/5.5/en/create-trigger.html CREATE TABLE test1(a1 INT); CREATE TABLE test2(a2 INT); CREATE TABLE test3(a3 INT NOT NULL AUTO_INCREMENT PRIMARY KEY); CREATE TABLE test4( a4 INT NOT NULL AUTO_INCREMENT PRIMARY KEY, b4 INT DEFAULT 0 ); delimiter | CREATE TRIGGER testref BEFORE INSERT ON test1 FOR EACH ROW BEGIN INSERT INTO test2 SET a2 = NEW.a1; DELETE FROM test3 WHERE a3 = NEW.a1; UPDATE test4 SET b4 = b4 + 1 WHERE a4 = NEW.a1; END; | delimiter ; MySQL Trigger Example
http://dev.mysql.com/doc/refman/5.5/en/create-trigger.html INSERT INTO test3 (a3) VALUES (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL); INSERT INTO test4 (a4) VALUES (0), (0), (0), (0), (0), (0), (0), (0), (0), (0); SELECT * FROM test1; 8 rows in set (0.00 sec) SELECT * FROM test2; 8 rows in set (0.00 sec) SELECT * FROM test3; 8 rows in set (0.00 sec) SELECT * FROM test4; 8 rows in set (0.00 sec) MySQL Trigger Example
http://dev.mysql.com/doc/refman/5.5/en/stored-routines.html The CREATE ROUTINE , ALTER ROUTINE , EXECUTE privilege is needed for stored routines. mysql> delimiter // mysql> CREATE PROCEDURE simpleproc (OUT param1 INT) -> BEGIN -> SELECT COUNT(*) INTO param1 FROM t; -> END// Query OK, 0 rows affected (0.00 sec) mysql> delimiter ; mysql> CALL simpleproc(@a); Query OK, 0 rows affected (0.00 sec) mysql> SELECT @a; +------+ | @a | +------+ | 3 | +------+ 1 row in set (0.00 sec) MySQL Stored Routines (Procedures and Functions)
http://dev.mysql.com/doc/refman/5.5/en/commit.html To disable autocommit mode, use the following statement: SET autocommit=0; To disable autocommit mode for a single series of statements, use the START TRANSACTION statement: START TRANSACTION; SELECT @A:=SUM(salary) FROM table1 WHERE type=1; UPDATE table2 SET summary=@A WHERE type=1; COMMIT; MySQL Transactions
MySQL Workbench SE Database Design •  Visual Design, modeling •  Forward/Reverse Engineer •  Schema validation, Schema doc SQL Development • SQL Editor - Color Syntax Highlighting • Objects - Import/Export, Browse/Edit • Connections - Wizard, SSH Tunnel Database Administration • Status, Configuration, Start/Stop • Users, Security, Sessions • Import/Export Dump Files Scripting & Plug-in Support UI Designed to match VS 2010 Saves you time developing and managing your MySQL apps. GA
MySQL Workbench - Plugins •  Community driven Plugins & Add-ons site –  Code in Python, share with the community
MySQL Workbench – Hands On Lab •  http://sqlhjalp.com/iso/OTN_Developer_Day_MySQL.iso
Additional Resources mysql.com •  TCO calculator •  White Papers •  Customer use cases and success stories dev.mysql.com •  Downloads •  Documentation •  Forums •  PlanetMySQL eDelivery.com •  Download and evaluate all MySQL products
Additional Resources mysql.com •  Download MySQL 5.5, MySQL Cluster 7.1 GA, GPL Products •  MySQL Products, Editions, Licensing Options •  TCO calculator •  Upcoming Events •  Customer use cases and success stories dev.mysql.com •  Download MySQL 5.6 DMR and Labs “early access” features •  Developer Zone Articles, How to’s eDelivery.com •  Download and evaluate all MySQL products
Additional Resources Planet.mysql.com •  Blog feeds from the experts and the community Books: •  MySQL by Paul DuBois •  MySQL Administrator's Bible •  High Performance MySQL: Optimization, Backups, Replication, and More forums.mysql.com •  Community interaction
<Insert Picture Here> Thanks for attending! keith.larson@oracle.com
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My sql regis_handsonlab

  • 1. <Insert Picture Here> MySQL: Regis Hands On Lab Keith Larson [email protected] MySQL Community Manager
  • 2. The following is intended to outline our general product direction. It is intended for information purposes only, and may not be incorporated into any contract. It is not a commitment to deliver any material, code, or functionality, and should not be relied upon in making purchasing decisions. The development, release, and timing of any features or functionality described for Oracle’s products remains at the sole discretion of Oracle. Safe Harbor Statement
  • 3. tar -xvf MySQL-5.5.16-1.rhel5.x86_64.tar rpm -i MySQL-server-5.5.16-1.rhel5.x86_64.rpm It will prompt you with setting passwords but I will show that soon. MySQL Installation
  • 5. -bash-3.2$ mysql mysql> create database world; ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'world' mysql> exit mysql -u root mysql> CREATE DATABASE world; mysql>exit; mysql -u root world < world_innodb.sql MySQL Denied
  • 6. -bash-3.2$ mysqladmin -u root password brad -bash-3.2$ mysql -u root world ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) -bash-3.2$ mysql -u root world -p Enter password: MySQL Set Root Password
  • 7. http://dev.mysql.com/doc/refman/5.5/en/grant.html mysql> CREATE USER 'monty'@'localhost' IDENTIFIED BY 'some_pass'; mysql> GRANT ALTER, CREATE VIEW, CREATE, DELETE, DROP, GRANT OPTION, INDEX, INSERT, SELECT, SHOW VIEW, TRIGGER, UPDATE ON *.* TO 'monty'@'localhost' WITH GRANT OPTION; mysql> CREATE USER 'monty'@'%' IDENTIFIED BY 'some_pass'; mysql> GRANT ALTER, CREATE VIEW, CREATE, DELETE, DROP, GRANT OPTION, INDEX, INSERT, SELECT, SHOW VIEW, TRIGGER, UPDATE ON *.* TO 'monty'@'%' WITH GRANT OPTION; mysql> flush privileges ; MySQL New Users
  • 8. http://dev.mysql.com/doc/refman/5.5/en/grant.html mysql> CREATE USER 'admin'@'localhost' IDENTIFIED BY 'admin_pass'; GRANT ALL ON *.* TO 'admin'@'localhost'; mysql> flush privileges ; mysql -u monty -p Enter password: mysql -u admin -p Enter password: MySQL New Super Users
  • 9. mysql -u admin -p mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | bobmason | | mysql | | performance_schema | | test | | world | +--------------------+ mysql> create database <yourname>_example; Query OK, 1 row affected (0.00 sec) MySQL Create Database/Schema
  • 10. mysql> use world; mysql> show tables; +-----------------+ | Tables_in_world | +-----------------+ | City | | Country | | CountryLanguage | +-----------------+ 3 rows in set (0.00 sec) mysql> show create table City; MySQL Table
  • 11. CREATE TABLE `City` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Name` char(35) NOT NULL DEFAULT '', `CountryCode` char(3) NOT NULL DEFAULT '', `District` char(20) NOT NULL DEFAULT '', `Population` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`), KEY `CountryCode` (`CountryCode`), CONSTRAINT `city_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) ) ENGINE=InnoDB AUTO_INCREMENT=4080 DEFAULT CHARSET=latin1 MySQL Table City
  • 12. mysql> use <yourname>_example; mysql> CREATE TABLE `City` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Name` char(35) NOT NULL DEFAULT '', `CountryCode` char(3) NOT NULL DEFAULT '', `District` char(20) NOT NULL DEFAULT '', `Population` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`), KEY `CountryCode` (`CountryCode`), CONSTRAINT `city_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) ) ENGINE=InnoDB ERROR 1005 (HY000): Can't create table '<yourname>_example.City' (errno: 150) http://forums.mysql.com/read.php?22,19755,19755 MySQL Create Table in Your Database
  • 13. mysql> show create table world.Country; mysql> CREATE TABLE `Country` ( -> `Code` char(3) NOT NULL DEFAULT '', -> `Name` char(52) NOT NULL DEFAULT '', -> `Continent` enum('Asia','Europe','North America','Africa','Oceania','Antarctica','South America') NOT NULL DEFAULT 'Asia', -> `Region` char(26) NOT NULL DEFAULT '', -> `SurfaceArea` float(10,2) NOT NULL DEFAULT '0.00', -> `IndepYear` smallint(6) DEFAULT NULL, -> `Population` int(11) NOT NULL DEFAULT '0', -> `LifeExpectancy` float(3,1) DEFAULT NULL, -> `GNP` float(10,2) DEFAULT NULL, -> `GNPOld` float(10,2) DEFAULT NULL, -> `LocalName` char(45) NOT NULL DEFAULT '', -> `GovernmentForm` char(45) NOT NULL DEFAULT '', -> `HeadOfState` char(60) DEFAULT NULL, -> `Capital` int(11) DEFAULT NULL, -> `Code2` char(2) NOT NULL DEFAULT '', -> PRIMARY KEY (`Code`) -> ) ENGINE=InnoDB; Query OK, 0 rows affected (0.02 sec) MySQL Try again ….
  • 14. Mysql> CREATE TABLE `City` ( -> `ID` int(11) NOT NULL AUTO_INCREMENT, -> `Name` char(35) NOT NULL DEFAULT '', -> `CountryCode` char(3) NOT NULL DEFAULT '', -> `District` char(20) NOT NULL DEFAULT '', -> `Population` int(11) NOT NULL DEFAULT '0', -> PRIMARY KEY (`ID`), -> KEY `CountryCode` (`CountryCode`), -> CONSTRAINT `city_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) -> ) ENGINE=InnoDB; Query OK, 0 rows affected (0.04 sec) MySQL City works now...
  • 15. Mysql> CREATE TABLE `CountryLanguage` ( `CountryCode` char(3) NOT NULL DEFAULT '', `Language` char(30) NOT NULL DEFAULT '', `IsOfficial` enum('T','F') NOT NULL DEFAULT 'F', `Percentage` float(4,1) NOT NULL DEFAULT '0.0', PRIMARY KEY (`CountryCode`,`Language`), KEY `CountryCode` (`CountryCode`), CONSTRAINT `countryLanguage_ibfk_1` FOREIGN KEY (`CountryCode`) REFERENCES `Country` (`Code`) ) ENGINE=InnoDB MySQL CountryLanguage as well..
  • 16. mysql> use <yourname>_example; mysql> insert into Country select * from world.Country; Query OK, 239 rows affected (0.03 sec) Records: 239 Duplicates: 0 Warnings: 0 mysql> insert into CountryLanguage select * from world.CountryLanguage; Query OK, 984 rows affected (0.03 sec) Records: 984 Duplicates: 0 Warnings: 0 mysql> insert into City select * from world.City; Query OK, 4079 rows affected (0.29 sec) Records: 4079 Duplicates: 0 Warnings: 0 Faster -- mysql -u admin -p <yourname>_example < world_innodb.sql MySQL Add Data
  • 17. SELECT ID , Name , CountryCode , Population FROM City WHERE CountryCode = 'USA' ORDER BY Population DESC limit 20; SELECT C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' ORDER BY C.Population DESC limit 20; MySQL Look at some data
  • 18. mysql> SELECT C.ID , C.Name , C.CountryCode , C.Population -> FROM City C -> INNER JOIN Country Y ON Y.Code = C.CountryCode -> INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode -> WHERE Y.Code = 'USA' -> ORDER BY Population DESC -> GROUP BY C.Name limit 20; MySQL Group by…
  • 19. mysql> SELECT C.ID , C.Name , C.CountryCode , C.Population -> FROM City C -> INNER JOIN Country Y ON Y.Code = C.CountryCode -> INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode -> WHERE Y.Code = 'USA' -> ORDER BY Population DESC -> GROUP BY C.Name limit 20; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP BY C.Name limit 20' at line 7 mysql> MySQL Group by…Error
  • 20. SELECT C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' GROUP BY C.Name ORDER BY Population DESC limit 20; MySQL Error fixed
  • 21. SET @RANK=0; # Variable SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' GROUP BY C.Name ORDER BY Population DESC limit 20; MySQL Rank Results
  • 22. SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' UNION SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.name = 'Denver' GROUP BY C.Name ORDER BY Population DESC limit 25; MySQL Union Example
  • 23. SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' UNION SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.name = 'Denver' GROUP BY C.Name ORDER BY Population DESC limit 25; ## Not what you wanted is it.... MySQL Union Example
  • 24. SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , DISTINCT(C.Name) as Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.Population >= 3694820 UNION SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' AND C.name = 'Denver' GROUP BY C.Name ORDER BY Population DESC limit 25; MySQL Union Example
  • 25. SET @RANK=0; SELECT @RANK:=@RANK+1 AS RANK, C.ID , C.Name , C.CountryCode , C.Population FROM City C INNER JOIN Country Y ON Y.Code = C.CountryCode INNER JOIN CountryLanguage L ON L.CountryCode = C.CountryCode WHERE Y.Code = 'USA' GROUP BY C.Name ORDER BY Population DESC limit 100 INTO OUTFILE '/tmp/mysql_export.csv' FIELDS TERMINATED BY ',' LINES TERMINATED BY 'n' MySQL Export Example
  • 26. http://dev.mysql.com/doc/refman/5.5/en/create-trigger.html CREATE TABLE test1(a1 INT); CREATE TABLE test2(a2 INT); CREATE TABLE test3(a3 INT NOT NULL AUTO_INCREMENT PRIMARY KEY); CREATE TABLE test4( a4 INT NOT NULL AUTO_INCREMENT PRIMARY KEY, b4 INT DEFAULT 0 ); delimiter | CREATE TRIGGER testref BEFORE INSERT ON test1 FOR EACH ROW BEGIN INSERT INTO test2 SET a2 = NEW.a1; DELETE FROM test3 WHERE a3 = NEW.a1; UPDATE test4 SET b4 = b4 + 1 WHERE a4 = NEW.a1; END; | delimiter ; MySQL Trigger Example
  • 27. http://dev.mysql.com/doc/refman/5.5/en/create-trigger.html INSERT INTO test3 (a3) VALUES (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL), (NULL); INSERT INTO test4 (a4) VALUES (0), (0), (0), (0), (0), (0), (0), (0), (0), (0); SELECT * FROM test1; 8 rows in set (0.00 sec) SELECT * FROM test2; 8 rows in set (0.00 sec) SELECT * FROM test3; 8 rows in set (0.00 sec) SELECT * FROM test4; 8 rows in set (0.00 sec) MySQL Trigger Example
  • 28. http://dev.mysql.com/doc/refman/5.5/en/stored-routines.html The CREATE ROUTINE , ALTER ROUTINE , EXECUTE privilege is needed for stored routines. mysql> delimiter // mysql> CREATE PROCEDURE simpleproc (OUT param1 INT) -> BEGIN -> SELECT COUNT(*) INTO param1 FROM t; -> END// Query OK, 0 rows affected (0.00 sec) mysql> delimiter ; mysql> CALL simpleproc(@a); Query OK, 0 rows affected (0.00 sec) mysql> SELECT @a; +------+ | @a | +------+ | 3 | +------+ 1 row in set (0.00 sec) MySQL Stored Routines (Procedures and Functions)
  • 29. http://dev.mysql.com/doc/refman/5.5/en/commit.html To disable autocommit mode, use the following statement: SET autocommit=0; To disable autocommit mode for a single series of statements, use the START TRANSACTION statement: START TRANSACTION; SELECT @A:=SUM(salary) FROM table1 WHERE type=1; UPDATE table2 SET summary=@A WHERE type=1; COMMIT; MySQL Transactions
  • 30. MySQL Workbench SE Database Design •  Visual Design, modeling •  Forward/Reverse Engineer •  Schema validation, Schema doc SQL Development • SQL Editor - Color Syntax Highlighting • Objects - Import/Export, Browse/Edit • Connections - Wizard, SSH Tunnel Database Administration • Status, Configuration, Start/Stop • Users, Security, Sessions • Import/Export Dump Files Scripting & Plug-in Support UI Designed to match VS 2010 Saves you time developing and managing your MySQL apps. GA
  • 31. MySQL Workbench - Plugins •  Community driven Plugins & Add-ons site –  Code in Python, share with the community
  • 32. MySQL Workbench – Hands On Lab •  http://sqlhjalp.com/iso/OTN_Developer_Day_MySQL.iso
  • 33. Additional Resources mysql.com •  TCO calculator •  White Papers •  Customer use cases and success stories dev.mysql.com •  Downloads •  Documentation •  Forums •  PlanetMySQL eDelivery.com •  Download and evaluate all MySQL products
  • 34. Additional Resources mysql.com •  Download MySQL 5.5, MySQL Cluster 7.1 GA, GPL Products •  MySQL Products, Editions, Licensing Options •  TCO calculator •  Upcoming Events •  Customer use cases and success stories dev.mysql.com •  Download MySQL 5.6 DMR and Labs “early access” features •  Developer Zone Articles, How to’s eDelivery.com •  Download and evaluate all MySQL products
  • 35. Additional Resources Planet.mysql.com •  Blog feeds from the experts and the community Books: •  MySQL by Paul DuBois •  MySQL Administrator's Bible •  High Performance MySQL: Optimization, Backups, Replication, and More forums.mysql.com •  Community interaction