Python Puzzlers - 2016 Edition

Python Puzzlers
Feb 17, 2016
Nandan Sawant, Ryan Rueth

Defaulter
def extend_list(val, l=[]):
l.append(val)
return l
list1 = extend_list(10)
list2 = extend_list(123,[])
list3 = extend_list('a')
print "list1 = %s" % list1

Defaulter
def extend_list(val, l=[]):
l.append(val)
return l
list1 = [10, 'a']
list2 = [123]
list3 = [10, 'a']

Defaulter
From the python documentation:
https://docs.python.org/2/reference/compound_stmts.html#function-definitions
● Avoid mutable default arguments
● If you use mutable default arguments,
○ don’t mutate them
○ have a good reason to mutate them (e.g. caching)

Defaulter
def extend_list(val, l=None):
if l is None:
l = []
l.append(val)
return l
list1 = [10]
list2 = [123]
list3 = ['a']

Who’s late?
multipliers = [lambda x: (i+1)*x for i in range(10)]
def print_multiplication_table_for(number):
print [multiplier(number) for multiplier in multipliers]
print_multiplication_table_for(2)

Who’s late?
multipliers = [lambda x: (i+1)*x for i in range(10)]
[20, 20, 20, 20, 20, 20, 20, 20, 20, 20]

Who’s late?
multipliers = []
for i in range(10):
def multiplier(x):
return (i+1) * x
multipliers.append(multiplier)

Who’s late?
multipliers = []
for i in range(10):
def multiplier(x):
return (i+1) * x
multipliers.append(multiplier)
[20, 20, 20, 20, 20, 20, 20, 20, 20, 20]

● A closure occurs when a function has access to a local variable from
an enclosing scope that has finished its execution
● Closures in python are late-binding
● This means that the values of variables used in closures are looked
up at the time the closure is called
● This behavior is NOT specific to lambdas
Who’s late?

Who’s late?
multipliers = [lambda x, i=i: (i+1)*x for i in range(10)]
[2, 4, 6, 8, 10, 12, 14, 16, 18, 20]

Who’s late?
from functools import partial
from operator import mul
multipliers = [partial(mul, i+1) for i in range(10)]
[2, 4, 6, 8, 10, 12, 14, 16, 18, 20]

Western Addition (A)
a = b = [1,2,3]
a += [4]
print a, b
a = a + [5]
print a, b

a = b = [1,2,3]
a += [4]
print a, b
a = a + [5]
print a, b
[1, 2, 3, 4] [1, 2, 3, 4]
[1, 2, 3, 4, 5] [1, 2, 3, 4]

● a + b uses __add__ while a += b uses __iadd__
● An object's __add__ method is regular addition: it takes two
parameters, returns their sum, and doesn't modify either parameter
● An object's __iadd__ method also takes two parameters, but makes
the change in-place, modifying the contents of the first parameter

Western Addition (B)
a = b = 'western'
a += 'addition'
print a, b
a = a + 'sf'
print a, b

a = b = 'western'
a += 'addition'
print a, b
a = a + 'sf'
print a, b
westernaddition western
westernadditionsf western

● a + b uses __add__ while a += b uses __iadd__, if it exists
● An object's __add__ method is regular addition: it takes two
parameters, returns their sum, and doesn't modify either parameter
● An object's __iadd__ method also takes two parameters, but makes
the change in-place, modifying the contents of the first parameter
● Because this requires object mutation, immutable types (like
Strings!) don’t have an __iadd__ method

Western Addition (C)
a = ([1,2,3],)
a[0] += [4]
print a

a = ([1,2,3],)
a[0] += [4]
print a
TypeError: 'tuple' object does
not support item assignment
([1, 2, 3, 4],)

● An object's __iadd__ method takes two parameters, but makes the
change in-place, modifying the contents of the first parameter and
returns the first parameter
● The code above is equivalent to:
a = ([1,2,3],)
x = a[0]
x = x.__iadd__([4]) # returns x itself
a[0] = x

Western Addition (D)
a = b = 500
print a is b
a -= 200
b -= 200
print a is b
a = a - 200
b = b - 200
print a is b
--a
--b
print a is b

a = b = 500
print a is b
a -= 200
b -= 200
print a is b
a = a - 200
b = b - 200
print a is b
--a
--b
print a is b
True
False
True
True

From the python documentation:
https://docs.python.org/2/c-api/int.html
● There is no decrement (--) operator in python
● -- is simply two negation operators

Crossing the Boundary (A)
a, b = 0, 1
def fib(n):
for i in range(n):
a, b = b, a + b
return a
print fib(4)

a, b = 0, 1
def fib(n):
for i in range(n):
a, b = b, a + b
return a
print fib(4)
UnboundLocalError: local
variable 'b' referenced before
assignment

x = 1
def f1():
print x
f1()
print x
x = 1
def f2():
x = 2
print x
f2()
print x
x = 1
def f3():
print x
x = 3
f3()
print x

x = 1
def f1():
print x
f1()
print x
x = 1
def f2():
x = 2
print x
f2()
print x
x = 1
def f3():
print x
x = 3
f3()
print x
1
1
2
1
UnboundLocalError: local
variable 'x' referenced
before assignment
1

● If we want to access a global variable from inside a function, it is
possible
● The assignment statement inside a function creates variables in the
local scope
● If a local variable has the same name as a global variable the local
variable will always take precedence
● The assignment inside the function does not modify the global
variable
● We may not refer to both a global variable and a local variable by
the same name inside the same function, it gives us an error
● Deep Dive http://eli.thegreenplace.net/2011/05/15/understanding-unboundlocalerror-in-python

a, b = 0, 1
def fib(n):
for i in range(n):
global a, b
a, b = b, a + b
return a
print fib(4) 3

Crossing the Boundary (C)
main.py
try:
import quitter
except:
exit(0)
quitter.quit()
quitter.py
def quit():
exit(0)
# Add one indented line here
# to make main.py crash
python main.py

main.py
try:
import quitter
except:
exit(0)
quitter.quit()
quitter.py
def quit():
exit(0)
exit = None
python main.py

main.py
try:
import quitter
except:
exit(0)
quitter.quit()
quitter.py
def quit():
exit(0)
exit = None
UnboundLocalError: local variable
'exit' referenced before assignment
python main.py

Kids These Days (A)
class Parent(object):
x = 1
class Child1(Parent):
pass
pass
print Parent.x, Child1.x, Child2.x
Child1.x = 2
Parent.x = 3

Kids These Days (A)
x = 1
pass
pass
Child1.x = 2
Parent.x = 3
1 1 1
1 2 1
3 2 3

● In Python, class variables are internally handled as dictionaries.
● If a variable name is not found in the dictionary of the current class,
the class hierarchy (i.e., its parent classes) are searched until the
referenced variable name is found
● If the referenced variable name is not found in the class itself or
anywhere in its hierarchy, an AttributeError occurs
Kids These Days (A)

Kids These Days (B)
class Parent:
x = 1
pass
x = 2
class GrandChild(Child1, Child2):
pass
print GrandChild.x

Kids These Days (B)
class Parent:
x = 1
pass
x = 2
pass
print GrandChild.x 1

Kids These Days (B)
x = 1
pass
x = 2
pass
print GrandChild.x 2

● If you don’t inherit from ‘object’, you’re defining an old style class
● MRO is Method Resolution Order. Lookup __mro__
● MRO for old style classes follows a native DFS approach
Grandchild -> Child 1 -> Parent -> Child 2 -> Parent
● MRO for new style classes is more sensible
Grandchild -> Child 1 -> Child 2 -> Parent
● Don’t use old-style classes
Kids These Days (B)

Exceptional Circumstances
user_id = 'a'
try:
user_id = int(user_id)
print user_id
except TypeError, ValueError:
print "Oops!"
(a) a
(b) 65
(c) Oops!
(d) raises TypeError
(e) raises ValueError

user_id = 'a'
try:
print user_id
except TypeError, ValueError:
print "Oops!"
(a) a
(b) 65
(c) Oops!
ValueError: invalid literal
for int() with base 10: 'a'

user_id = 'a'
try:
print user_id
except (TypeError, ValueError):
print "Oops!"
(a) a
(b) 65
(c) Oops!

● If you’re catching multiple exceptions in python 2.x,
you must enclose them in parentheses
● If you do not, the second argument to except is treated as a
reference to the exception object. E.g. this may look familiar:
except Exception, e
● This problem goes away in python 3.x as
except Exception, e
is not a valid syntax. It is replaced by
except Exception as e

So long!
x = set([type(1), type(1L), type(1.0)])
y = set([1.__class__, 1L.__class__, 1.0.__class__])
print x == y
(a) True
(b) False
(c) TypeError
(d) None of the above

So long!
print x == y
(a) True
(b) False
(c) TypeError
^
SyntaxError: invalid syntax

It is a tokenization issue!
The . is parsed as the beginning of the fractional part of a floating point
number. When it encounters something other than a number, it will
throw an error.
So long!

So long!
y = set([(1).__class__, 1L.__class__, 1.0.__class__])
print x == y
(a) True
(b) False
(c) TypeError

Zilch
z = False
i = []
l = 0,
c = None
h = {}
print any((z, i, l, c, h))
(a) True
(b) False
(c) (False, False, False, False, False)

When creating a tuple, in all cases except the empty tuple, the comma
is the important thing.
Parentheses are only required for other syntactic reasons: to distinguish
a tuple from a set of function arguments, operator precedence, or to
allow line breaks.
Zilch
https://docs.python.org/2/tutorial/datastructures.html#tuples-and-sequences

It’s 2016!
print 2,016 * 2,016
(a) 4064256
(b) 4,064,256
(c) 4 256
(d) 2 32 16
(e) None of the above

It’s 2016!
print 2,016 * 2,016
(a) 4064256
(b) 4,064,256
(c) 4 256
(d) 2 32 16
(e) None of the above
2 28 14

The 0 is an outdated prefix that Python 2.x uses
to represent Octal numbers.
In Python 3, you must write: 0o16 instead.
It’s 2016!

Finally
def find_inverse(n):
inverse = 1
try:
inverse = 1 / k
finally:
return inverse
fi = find_inverse
print fi(-1) + fi(0) + fi(1)
(a) 0
(b) 1
(c) 3
(d) raises ZeroDivisionError
(e) raises NameError
(f) None of the above

return in finally will swallow the actual return value in the try block
return in finally will swallow the exception
Finally

References
● How to format code within a presentation
● Python Puzzlers by Tendayi Mawushe at PyCon Ireland 2010
● Python Puzzlers by Alan Pierce at Khan Academy
● Python Epiphanies by Stuart Williams at PyCon Montreal 2015
● Python Interview Questions
● Python Gotchas
● Raymon Hettinger’s twitter feed @raymondh

Python Puzzlers - 2016 Edition

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